FizzBuzz Solution Dumping Ground
One solution in Erlang with recursion. -module(fizzbuzz). -export([print/0]). print() -> FizzBuzzList = eval(100, []), lists:foreach(fun(Item)->io:format("~p~n", [Item]) end, FizzBuzzList)....
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Old but gold, vb6: Dim i As Integer Open "C:\output.txt" For Append As #1 ' VB6 does not have native console window support For i=1 To 100 If i Mod 3 = 0 Then Print #1, "Fizz" If i Mod 5 = 0 Then...
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My 2 cents in Perl. Not the shortest, but it is among the most compact and still readable, doesn’t cheat using a module that does the work and is not exposed, and most importantly, it works CORRECTLY...
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This one is simpler, more readable, and no ternary ops: while ($i++ < 100){ my $out; $out = "Fizz" unless ($i%3); $out .= "Buzz" unless ($i%5); say "$out" || "$i"; } # ... and oh, it works...
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Of course we couldn’t forget our both loved and hated VBA in all its glory Normal Loop: Sub FizzBuzz(n As Integer) Dim i As Integer For i = 1 To n If i Mod 3 = 0 And i Mod 5 = 0 Then Debug.Print...
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FizzBuzz Solution Dumping Ground
Matt_Giuca: Uh, someone ordered an x86 assembly version? Now imagine that poor soul that made Roller Coaster 2, ALL in assembly… Read full topic
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Let’s go python: def FizzBuzz(highestNumber, numbers, words): for i in range(1, highestNumber + 1): out = "" for number, word in zip(numbers, words): if i % number == 0: out += word print(out if out...
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Python, could be more compact but this way it is more clear what the program does and less computation only mod two times instead of four. for i in range(0,101): fizz = i % 5 == 0 buzz = i % 3 == 0 if...
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In java, but in functional paradigm (don’t do this at work). public static void main(String[] args) { final String result = IntStream .rangeClosed(1, 100) .mapToObj(Scratch::fizzBuzz)...
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And since no one seems to have picked MUMPS in thirteen years of responses: F I=1:1:100 W !,$S(I#15=0:"Fizzbuzz",I%3=0:"Fizz",I%5=0:"Buzz",1:I) Read full topic
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Surprised no one posted this efficient solution so far. I’ll post it in PHP I guess, but the concept works in most languages. function FizzBuzz($limit = 100, $FizzMultiple=3, $BuzzMultiple=5){...
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FizzBuzz Solution Dumping Ground
Well I read the article and knew I had to dump my JS solution for it var i; for (i = 1; i < 101; i++) { if((i%3==0) && (i%5==0)) { console.log("FizzBuzz"); } else if(i%3==0) {...
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FizzBuzz Solution Dumping Ground
I tried this simple code for number in range(101): if number%15 == 0 : print("FizzBuzz") elif number%5 == 0: print("Buzz") elif number%3 == 0: print("Fizz") else: print(number) Read full topic
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Surprised nobody has posted this here yet… Coding in Stenography, Quick Demo Read full topic
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for num in range(1,100): if num % 3 == 0: print("Fizz", num) elif num % 5 == 0: print("Buzz", num) elif num % 3 == 0 and num % 5 == 0: print("FizzBuzz", num) elif num % 1 == 0: print("Prime", num)...
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Thank you for liking my code. I also wrote two different paper, scissors, rock program but was difficult at the start and abstract but I put mind to work and think and think with music. I am a...
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Java Solution class Main { public static void main(String[] args) { int i = 0; while (i != 101) { if ((i % 3 == 0)&(i % 5 != 0)){ System.out.println("Fizz"); } else if ((i % 3 != 0)&(i % 5 ==...
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Many have done it, now it’s my turn… <?php for ($i=1; $i<=100; $i++) { $string = ''; $string = $i%3==0 ? $string.'Fizz' : $string; $string = $i%5==0 ? $string.'Buzz' : $string; $string = $string...
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Someone decided (in a fit of self mutilation) to optimize fizzbuzz using assembly: fastest code - High throughput Fizz Buzz - Code Golf Stack Exchange Read full topic
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A late entry for GameMaker, with something they call ‘commenting’ and some ‘color’. Could be made more efficient but I was going for speed and clarity: //DRAW STEP var pos_x = 20; var pos_y = 5; var...
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